document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=181601>Question 181601</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Okay this is my last question. <BR>\n" );
document.write( "on this itsays...\r<BR>\n" );
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document.write( "14-2i Over 3+i.<BR>\n" );
document.write( "I dont know if that makes sense to you\r<BR>\n" );
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document.write( "But i think i learned something about taking the conjucate of 3+i which is 3-1, but i dont know where to go from there, or if im even doing it right.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #136201 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=136201\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 14-2i Over 3+i.<BR>\n" );
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document.write( "= [(14-2i)(3-i)] / [(3+i)(3-i)]\r<BR>\n" );
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document.write( "(42-14i-6i-2) / (9+1}\r<BR>\n" );
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document.write( "= (40-20i)/10\r<BR>\n" );
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document.write( "= (20 - 10i)/ 5\r<BR>\n" );
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document.write( "= 4 - 2i<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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