document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=181587>Question 181587</A>: <I><SPAN STYLE=\"word-break: break-all;\"> forty ounces of a 30% gold alloy are mixed with 54 ounces of a 20% alooy. Find the concentration of teh resulting gold alloy. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #136173 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=136173\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> forty ounces of a 30% gold alloy are mixed with 54 ounces of a 20% alooy. Find the concentration of teh resulting gold alloy.<BR>\n" );
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document.write( "40 oz x 0.3 = 12 oz of gold<BR>\n" );
document.write( "54 oz x 0.2 = 10.8 oz of gold<BR>\n" );
document.write( "12 + 10.8 = 22.8 oz of gold<BR>\n" );
document.write( "40 + 54 = 94 oz total<BR>\n" );
document.write( "22.8/94 = 0.24255...<BR>\n" );
document.write( "= 24.26%<BR>\n" );
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document.write( "The answer seems reasonable, as it's between the 2 percentages, and closer to the one that most of was used.<BR>\n" );
document.write( "Always check your answers for reasonableness.  If a mistake had been made, and the answer came out as 48%, or 12%, you should recognize that something is wrong. </SPAN>\n" );
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