document.write( "Question 181561This question is from textbook Algebra and Trigonometry Structure and Method
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document.write( ": Pipes A and B can fill a storage tank in 8 hours and 12 hours, respectivley. With the tank empty, pipe A was turned on at noon , and then pipe B was turned on at 1:30 pm. At what time ws the tank full? \n" );
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Algebra.Com's Answer #136160 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Pipes A and B can fill a storage tank in 8 hours and 12 hours, respectively. With the tank empty, pipe A was turned on at noon , and then pipe B was turned on at 1:30 pm. At what time was the tank full? \n" ); document.write( ": \n" ); document.write( "Let t = the \"on\" time duration of pipe A \n" ); document.write( "then \n" ); document.write( "(t-1.5) = the \"on\" time of pipe B \n" ); document.write( ": \n" ); document.write( "Let the completed job = 1; (a full tank) \n" ); document.write( ": \n" ); document.write( "A shared work equation: \n" ); document.write( " \n" ); document.write( "Multiply equation by 24 to get rid of the denominators, results: \n" ); document.write( "3t + 2(t-1.5) = 24(1) \n" ); document.write( "; \n" ); document.write( "3t + 2t - 3 = 24 \n" ); document.write( ": \n" ); document.write( "5t = 24 + 3 \n" ); document.write( "t = \n" ); document.write( "t = 5.4 hrs, which is 5 hrs + (.4*60) = 5 hrs, 24 min \n" ); document.write( ": \n" ); document.write( "we can say the tank will be full at 5:24 pm \n" ); document.write( "; \n" ); document.write( ": \n" ); document.write( "Check solution; pipe B time: 5.4 - 1.5 = 3.9 hrs \n" ); document.write( " \n" ); document.write( ".625 + .325 = 1; confirms our solution \n" ); document.write( " |