document.write( "Question 181478: The radiator in a car is filled with a solution of 65 per cent antifreeze and 35 per cent water. The manufacturer of the antifreeze suggests that for summer driving, optimal cooling of the engine is obtained with only 50 per cent antifreeze. If the capacity of the raditor is 3 liters, how much coolant (in liters) must be drained and replaced with pure water to reduce the antifreeze concentration to 50 per cent? \n" ); document.write( "
Algebra.Com's Answer #136098 by stanbon(75887)\"\" \"About 
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The radiator in a car is filled with a solution of 65 per cent antifreeze and 35 per cent water.
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\n" ); document.write( "The manufacturer of the antifreeze suggests that for summer driving, optimal cooling of the engine is obtained with only 50 per cent antifreeze.
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\n" ); document.write( "If the capacity of the raditor is 3 liters, how much coolant (in liters) must be drained and replaced with pure water to reduce the antifreeze concentration to 50 per cent?
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\n" ); document.write( "antifreeze - antifreeze + + antifreeze = antifreeze
\n" ); document.write( "0.65*3 - 0.65x + 0*x = 0.50*3 \r
\n" ); document.write( "\n" ); document.write( "Multiply thru by 100 to get:\r
\n" ); document.write( "\n" ); document.write( "65*3 - 65x + 0*x = 50*3\r
\n" ); document.write( "\n" ); document.write( "195 = 65x + 0 = 150
\n" ); document.write( "-65x = -45
\n" ); document.write( "x = 9/13 liters (amt. of liguid that must be replace)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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