document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=181471>Question 181471</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If x=a, it follows that x^2=ax<BR>\n" );
document.write( "               Thus     x^2 - a^2 =ax - a^2<BR>\n" );
document.write( "                or     (a+x)(x-a) = a(x-a)<BR>\n" );
document.write( "              therefore      x+a  = a<BR>\n" );
document.write( "                               2a = a<BR>\n" );
document.write( "                                2= 1\r<BR>\n" );
document.write( "\n" );
document.write( "Now I know 2 is not = 1. I am strugglling to figure out where I went wrong in the sum I tried to solve above. Please help!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #136087 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=136087\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If x=a, it follows that x^2=ax<BR>\n" );
document.write( "Thus x^2 - a^2 =ax - a^2<BR>\n" );
document.write( "or (a+x)(x-a) = a(x-a)<BR>\n" );
document.write( "------------------------------------------<BR>\n" );
document.write( "Cancelling the (x-a) is dividing by zero.  All that follows is meaningless.<BR>\n" );
document.write( "------------------------------------------<BR>\n" );
document.write( "therefore x+a = a<BR>\n" );
document.write( "2a = a<BR>\n" );
document.write( "2= 1 <BR>\n" );
document.write( "Now I know 2 is not = 1. I am strugglling to figure out where I went wrong in the sum I tried to solve above. Please help!! </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );