document.write( "Question 181439: an orange grower has 400 crates or fruit ready and will have 20 more for each day the grower waits to sell. the present price is $60 per crate and will drop $2 per crate per day. in how many days should the grower ship the crop to maximize income? \n" ); document.write( "

Algebra.Com's Answer #136051 by stanbon(75887) $\"\"$ $\"About$

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an orange grower has 400 crates of fruit ready and will have 20 more for each day the grower waits to sell. the present price is $60 per crate and will drop $2 per crate per day. in how many days should the grower ship the crop to maximize income?
\n" ); document.write( "---------------------------------------
\n" ); document.write( "Revenu = price * quantity\r
\n" ); document.write( "\n" ); document.write( "R(x) = (60 - 2x)(400 + 20x)\r
\n" ); document.write( "\n" ); document.write( "R(x) = 2(30-x)*20(20+x)\r
\n" ); document.write( "\n" ); document.write( "R(x) = -40(x-30)(x+20)
\n" ); document.write( "R(x) = -40(x^2 - 10x - 600)\r
\n" ); document.write( "\n" ); document.write( "--------------------------------
\n" ); document.write( "Max of min occurs when x = -b/2a = 10/2 = 5
\n" ); document.write( "Maximum revenue will occur on day 5
\n" ); document.write( "============================================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "

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