document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=181436>Question 181436</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A chemist needs 10 L of a 50% alcohol solution. She must mix a 40% solution and a 65% solution. How many liters of each required to obtain what she needs? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #136045 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=136045\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A chemist needs 10 L of a 50% alcohol solution. She must mix a 40% solution and a 65% solution. How many liters of each required to obtain what she needs?<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "alcohol + alcohol = alcohol<BR>\n" );
document.write( "0.40x + 0.65(10-x) = 0.50*10\r<BR>\n" );
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document.write( "Multiply thru by 100 to get:\r<BR>\n" );
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document.write( "40x + 65(10-x) = 50*10\r<BR>\n" );
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document.write( "40x + 650 - 65x = 500\r<BR>\n" );
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document.write( "-25x = -150\r<BR>\n" );
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document.write( "x = 6 L (amt. of 40% solution in the mixture)<BR>\n" );
document.write( "10-x = 4 L (amt. of 65% solution in the mixture)\r<BR>\n" );
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document.write( "================================================================<BR>\n" );
document.write( "Cheers<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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