document.write( "Question 181435: Five years ago, Tom was one third as old as his father was then. In 5 years, Tom will be half as old as his father will be then. Find their ages now. \n" ); document.write( "
Algebra.Com's Answer #136043 by scott8148(6628)![]() ![]() You can put this solution on YOUR website! let t=\"Tom now\", and f=\"father now\"\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "\"Five years ago, Tom was one third as old as his father was then\" \n" ); document.write( "... 3(t-5) = f-5 \n" ); document.write( "distributing ... 3t-15 = f-5 \n" ); document.write( "adding 5 ... 3t-10 = f\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "\"In 5 years, Tom will be half as old as his father will be then\" \n" ); document.write( "... 2(t+5) = f+5 \n" ); document.write( "distributing ... 2t+10 = f+5 \n" ); document.write( "subtracting 5 ... 2t+5 = f\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "substituting ... 3t-10 = 2t+5 \n" ); document.write( "adding 10-2t ... t = 15\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "substituting ... 2(15)+5 = f ... 35 = f \n" ); document.write( " |