document.write( "Question 181362: im now sure i need HELP PLEASE
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document.write( "If the illumination of a book 9m from a lamp is 150 lumens/m^2 find the illumination of the book 3m closer to the lamp...
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document.write( "I got 225 lm/m^2????????????????????? \n" );
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Algebra.Com's Answer #135980 by Alan3354(69443) You can put this solution on YOUR website! im now sure i need HELP PLEASE \n" ); document.write( "If the illumination of a book 9m from a lamp is 150 lumens/m^2 find the illumination of the book 3m closer to the lamp... \n" ); document.write( "I got 225 lm/m^2????????????????????? \n" ); document.write( "-------------------- \n" ); document.write( "It's an inverse square relationship, common in nature. \n" ); document.write( "i = k/d^2 (illumination = a constant/the distance squared) \n" ); document.write( "150 = k/9^2 \n" ); document.write( "k = 150*81 = 12150 \n" ); document.write( "------------ \n" ); document.write( "@ 6 meters: \n" ); document.write( "i = 12150/6^2 = 12150/36 \n" ); document.write( "i = 337.5 lm/m^2 \n" ); document.write( " \n" ); document.write( " |