document.write( "Question 181264: the total surface area of a hollow cylinder which is open fron both sides is 4620cm2.area of base ring is 115.5cm2 and height is 7 cm. find the thickness of the cylinder \n" ); document.write( "
Algebra.Com's Answer #135972 by ankor@dixie-net.com(22740)\"\" \"About 
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The given height of 7cm makes no sense, I changed the height to 70 cm.
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\n" ); document.write( "The total surface area of a hollow cylinder, which is open from both sides, is 4620cm2. Area of base ring is 115.5cm2, and height is 70 cm.
\n" ); document.write( " Find the thickness of the cylinder
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\n" ); document.write( "I assume the \"total surface area\" is the surfaces of both the inside and
\n" ); document.write( "the outside of the cylinder,
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\n" ); document.write( "Surface area of just the outside: 4620/2 = 2310 sq/cm
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\n" ); document.write( "Surface area = circumference * height
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\n" ); document.write( "Find the circumference: 2310/70 = 33 cm
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\n" ); document.write( "Find the diameter:
\n" ); document.write( " d*pi = 33;
\n" ); document.write( " d = 33/pi;
\n" ); document.write( " d = 10.5 cm diameter of the cylinder
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\n" ); document.write( "Find the diameter of the base
\n" ); document.write( "pi*r^2 = 115.5
\n" ); document.write( "r^2 = \"115.5%2Fpi\"
\n" ); document.write( "r^2 = 36.6
\n" ); document.write( "r = \"sqrt%2836.6%29\"
\n" ); document.write( "r = 6.05 cm
\n" ); document.write( "d = 12.1 cm diameter of the base
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\n" ); document.write( "12.1 - 10.5 = 1.6 cm
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\n" ); document.write( "Thickness = \"1.6%2F2\" = .8 cm
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\n" ); document.write( "Let me know if I assumed right here. Carl \n" ); document.write( "
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