document.write( "Question 181294This question is from textbook
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document.write( ": Claim: The mean time between uses of a TV remote control by males during commercials equals 5.0 seconds. Find the test statistic, p-value, critical value(s), and state the final conclusion. \r
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document.write( "Sample data: n = 80, x-bar = 5.25 sec. Assume that s = 2.50 sec and the significance level is a = .01. (Use p-value approach)
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Algebra.Com's Answer #135937 by stanbon(75887) ![]() You can put this solution on YOUR website! Claim: The mean time between uses of a TV remote control by males during commercials equals 5.0 seconds. Find the test statistic, p-value, critical value(s), and state the final conclusion. \r \n" ); document.write( "\n" ); document.write( "Sample data: n = 80, x-bar = 5.25 sec. Assume that s = 2.50 sec and the significance level is a = .01. (Use p-value approach) \n" ); document.write( "------------------------------- \n" ); document.write( "Comment: You have not indicated if you have been told to use a Z-test \n" ); document.write( "or a T-test. \n" ); document.write( "------------------- \n" ); document.write( "I'll use Z-test Data: \n" ); document.write( "critical value for right-tail test with alpha = 1% is z = 2.326 \n" ); document.write( "test statistic: z(5.25) = (5.25-5)/[2.5/(sqrt(80)] = 0.8944.. \n" ); document.write( "------------------------ \n" ); document.write( "Assuming you are performing a right-tail test, the p-value \n" ); document.write( "is P(z>0.8944) = 0.1855.. = 18.55% \n" ); document.write( "----------------------------------------- \n" ); document.write( "Conclusion: Since p-value is greater than 1%, Fail to reject Ho. \n" ); document.write( "=================================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |