document.write( "Question 181261: The sum of two numbers is 43. Twice the larger number exceeds three times the smaller numner by 16. Find the number \n" ); document.write( "
Algebra.Com's Answer #135911 by eperette(173)![]() ![]() ![]() You can put this solution on YOUR website! x + y = 43 \n" ); document.write( "2y = 3x + 16\r \n" ); document.write( "\n" ); document.write( "***** \n" ); document.write( "x + y = 43 \n" ); document.write( "x +-x + y = 43 -x \n" ); document.write( "0 + y = 43 - x \n" ); document.write( "y = 43 - x\r \n" ); document.write( "\n" ); document.write( "2y = 3x + 16 \n" ); document.write( "2(43 - x) = 3x + 16 \n" ); document.write( "2(43) + 2(-x) = 3x + 16 \n" ); document.write( "86 - 2x = 3x + 16 \n" ); document.write( "86 - 2x + 2x = 3x + 2x + 16 \n" ); document.write( "86 - 0 = 5x + 16 \n" ); document.write( "86 - 16 = 5x + 16 - 16 \n" ); document.write( "70 = 5x + 0 \n" ); document.write( "70/5 = 5x/5 \n" ); document.write( "14 = x\r \n" ); document.write( "\n" ); document.write( "then \n" ); document.write( "y = 43 -x \n" ); document.write( "y = 43 - 14 \n" ); document.write( "y = 29\r \n" ); document.write( "\n" ); document.write( ">>>>>>>CHECK>>>>>> \n" ); document.write( "14 + 29 = 43\r \n" ); document.write( "\n" ); document.write( "2(29)= 58 \n" ); document.write( "3(14)= 42 \n" ); document.write( "58 - 42 = 16\r \n" ); document.write( "\n" ); document.write( "RIGHT\r \n" ); document.write( "\n" ); document.write( "so the smallest number x=14 and the larger number y=29 \n" ); document.write( " |