document.write( "Question 181055: A jar with pennies, nickels, and dimes contains a total of 55 coins worth $3.23. How many of each are there if the number of pennies is 10 less than the sum of nickels and dimes together? \n" ); document.write( "
Algebra.Com's Answer #135905 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!
YOU NEED TO RECHECK YOUR PROBLEM. UNLESS I MADE A MISTAKE, WE ARE COMING OUT WITH FRACTIONS OF COINS AND WE CAN'T HAVE FRACTIONS OF COINS.
\n" ); document.write( "Let x=number of pennies
\n" ); document.write( "y=number of nickels
\n" ); document.write( "z=number of dimes
\n" ); document.write( "Then:
\n" ); document.write( "x+y+z=55-----------------eq1
\n" ); document.write( "Lets deal in pennies
\n" ); document.write( "x+5y+10z=323------------------eq2\r
\n" ); document.write( "\n" ); document.write( "and
\n" ); document.write( "x+10=y+z or
\n" ); document.write( "x-y-z=-10 or
\n" ); document.write( "x-(y+z)=-10----------------------eq3
\n" ); document.write( "but from eq1, y+z=55-x. Substitute this into eq3
\n" ); document.write( "x-(55-x)=-10 or
\n" ); document.write( "x-55+x=-10 add 55 to each side
\n" ); document.write( "2x=45-----------------------------------------NO GOOD!!!!\r
\n" ); document.write( "\n" ); document.write( "LET'S TRY ANOTHER APPROACH:\r
\n" ); document.write( "\n" ); document.write( "subtract eq1 from eq2 and we get:
\n" ); document.write( "4y+9z=268-----------------------------------eq1a
\n" ); document.write( "subtract eq3 from eq2 and we get:
\n" ); document.write( "6y+11z=333------------------------------------eq2a\r
\n" ); document.write( "\n" ); document.write( "Multiply eq1a by 3:
\n" ); document.write( "12y+27z=804----------------------eq1b
\n" ); document.write( "Multiply eq2a by 2:
\n" ); document.write( "12y+22z=666--------------------------eq2b
\n" ); document.write( "subtract eq2b from eq1b:
\n" ); document.write( "5z=138-------------------------------------------NO GOOD!!!!!\r
\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor\r
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