document.write( "Question 181055: A jar with pennies, nickels, and dimes contains a total of 55 coins worth $3.23. How many of each are there if the number of pennies is 10 less than the sum of nickels and dimes together? \n" ); document.write( "
Algebra.Com's Answer #135905 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! YOU NEED TO RECHECK YOUR PROBLEM. UNLESS I MADE A MISTAKE, WE ARE COMING OUT WITH FRACTIONS OF COINS AND WE CAN'T HAVE FRACTIONS OF COINS. \n" ); document.write( "Let x=number of pennies \n" ); document.write( "y=number of nickels \n" ); document.write( "z=number of dimes \n" ); document.write( "Then: \n" ); document.write( "x+y+z=55-----------------eq1 \n" ); document.write( "Lets deal in pennies \n" ); document.write( "x+5y+10z=323------------------eq2\r \n" ); document.write( "\n" ); document.write( "and \n" ); document.write( "x+10=y+z or \n" ); document.write( "x-y-z=-10 or \n" ); document.write( "x-(y+z)=-10----------------------eq3 \n" ); document.write( "but from eq1, y+z=55-x. Substitute this into eq3 \n" ); document.write( "x-(55-x)=-10 or \n" ); document.write( "x-55+x=-10 add 55 to each side \n" ); document.write( "2x=45-----------------------------------------NO GOOD!!!!\r \n" ); document.write( "\n" ); document.write( "LET'S TRY ANOTHER APPROACH:\r \n" ); document.write( "\n" ); document.write( "subtract eq1 from eq2 and we get: \n" ); document.write( "4y+9z=268-----------------------------------eq1a \n" ); document.write( "subtract eq3 from eq2 and we get: \n" ); document.write( "6y+11z=333------------------------------------eq2a\r \n" ); document.write( "\n" ); document.write( "Multiply eq1a by 3: \n" ); document.write( "12y+27z=804----------------------eq1b \n" ); document.write( "Multiply eq2a by 2: \n" ); document.write( "12y+22z=666--------------------------eq2b \n" ); document.write( "subtract eq2b from eq1b: \n" ); document.write( "5z=138-------------------------------------------NO GOOD!!!!!\r \n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |