document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=25358>Question 25358</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 3m less than twice the width. the perimeter of the rectangle is 42m. find the length and the width of the rectangle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #13588 by </B><A HREF=/tutors/aboutme.mpl?userid=Paul><B>Paul(988)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Paul><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=13588\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Length = 2x-3<BR>\n" );
document.write( "Width = x<BR>\n" );
document.write( "Perimenter = 42<BR>\n" );
document.write( "Formula = 2(L+W)=P<BR>\n" );
document.write( "2(2x-3+x)=42<BR>\n" );
document.write( "2(3x-3)=42<BR>\n" );
document.write( "6x-6=42<BR>\n" );
document.write( "6x=48<BR>\n" );
document.write( "x=8<BR>\n" );
document.write( "2(8)-3=13\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Hence the width is 6m and the length is 9m.<BR>\n" );
document.write( "Paul.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );