document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=181208>Question 181208</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a 3M BAR is used to lift a stone. A 90 kg person exerts all his weight to one end of the bar which is 2 1/2 m from the fulcrum and balances the stone. The weight of the stone is approximately?<BR>\n" );
document.write( "PLEASE I AM ASKING FOR HELP, WHO CAN ANSWER MY PRAYER....... </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #135863 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=135863\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a 3M BAR is used to lift a stone. A 90 kg person exerts all his weight to one end of the bar which is 2 1/2 m from the fulcrum and balances the stone. The weight of the stone is approximately?<BR>\n" );
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document.write( "weight*length = weight*length<BR>\n" );
document.write( "90*(5/2) = x*3\r<BR>\n" );
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document.write( "30(5/2) = x\r<BR>\n" );
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document.write( "x = 75 kg (the weight of the stone)\r<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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