document.write( "Question 181203: (1/3)^2-x=27^3+x \n" ); document.write( "

Algebra.Com's Answer #135853 by Alan3354(69443) $\"\"$ $\"About$

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(1/3)^2-x=27^3+x
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\n" ); document.write( "I'll assume the exponents are (2-x) and (3+x).
\n" ); document.write( "(1/3)^(2-x) = 3^(x-2)
\n" ); document.write( "And, 27^(3+x) = 3^(9+3x) (27 = 3^3)
\n" ); document.write( "So,
\n" ); document.write( "3^(x-2) = 3^(3x+9)
\n" ); document.write( "x-2 = 3x+9
\n" ); document.write( "2x = -11
\n" ); document.write( "x = -11/2 \n" ); document.write( "

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