document.write( "Question 25338: 8x-(x-5)is greater than x plus 17\r
\n" ); document.write( "\n" ); document.write( "i dont have the slightest clue how to solve this problem.
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Algebra.Com's Answer #13583 by longjonsilver(2297)\"\" \"About 
You can put this solution on YOUR website!
8x-(x-5) > x+17 means fully... 8x-1*(x-5) > x+17... the 1* is the important bit to know about. Why don't we write it? because we know it is there by not writing it! :-)\r
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\n" ); document.write( "\n" ); document.write( "and then -1*x is -1x or just -x
\n" ); document.write( "and also -1*-5 is +5\r
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\n" ); document.write( "\n" ); document.write( "so we have 8x-x+5 > x+17
\n" ); document.write( "or 7x+5 > x+17
\n" ); document.write( "so 6x+5 > 17
\n" ); document.write( "then 6x > 12
\n" ); document.write( "finally x > 12/6
\n" ); document.write( "giving x > 2\r
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\n" ); document.write( "\n" ); document.write( "jon.
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