document.write( "Question 181115: an athlete covered a distance of 57 miles by walking for 2 hours and then riding a bicycle for the remainder of the trip. her rate increased by 10 mph on the bike. if the entire trip took 5 1/2 hours, what was her riding rate? \n" ); document.write( "
Algebra.Com's Answer #135828 by ankor@dixie-net.com(22740)\"\" \"About 
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An athlete covered a distance of 57 miles by walking for 2 hours, and then
\n" ); document.write( " riding a bicycle for the remainder of the trip. His rate increased by 10 mph
\n" ); document.write( " on the bike. If the entire trip took 5 1/2 hours, what was his riding rate?
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\n" ); document.write( "Let s = the riding rate
\n" ); document.write( "then
\n" ); document.write( "(s-10) = the walking rate
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\n" ); document.write( "From the given information, he walked 2 hrs, therefore, he biked 3.5 hr
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\n" ); document.write( "Write a distance equation: dist = time * speed
\n" ); document.write( "Walk dist + bike dist = 57 mi
\n" ); document.write( "2(s-10) + 3.5s = 57
\n" ); document.write( ":
\n" ); document.write( "2s - 20 + 3.5s = 57
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\n" ); document.write( "5.5s = 57 + 20
\n" ); document.write( "s = \"77%2F5.5\"
\n" ); document.write( "s = 14 mph on the bike
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\n" ); document.write( "Check solution by finding the distances (14 - 10 = 4 mph walking):
\n" ); document.write( "3.5*14 = 49 mi
\n" ); document.write( "2 * 4 = 8 mi
\n" ); document.write( "-------------
\n" ); document.write( "total = 57 mi \n" ); document.write( "
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