document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=181161>Question 181161</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0395937787/algebrahomeworkh>algebra 2</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> solve:\r<BR>\n" );
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document.write( "cuberoot of 2x+15-3/2 times cuberoot of x=0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #135819 by </B><A HREF=/tutors/aboutme.mpl?userid=eperette><B>eperette(173)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=eperette><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=135819\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> cuberoot(2x+15) - (3/2cuberoot(x)) = 0<BR>\n" );
document.write( "cuberoot(2x + 15) = 3/2cuberoot(x)<BR>\n" );
document.write( "(cuberoot(2x+15))^3 = (3/2cuberoot(x))^3<BR>\n" );
document.write( "2x + 15 = (3/2)^3(x)<BR>\n" );
document.write( "2x + 15 = (27/8)(x)<BR>\n" );
document.write( "2x-2x + 15 = (27/8)x - 2x<BR>\n" );
document.write( "0 + 15 = (27/8)x - (16/8)x<BR>\n" );
document.write( "15 = (11/8)x<BR>\n" );
document.write( "8(15) = 8(11/8)x<BR>\n" );
document.write( "120 = 11x<BR>\n" );
document.write( "120/11 = 11x/11<BR>\n" );
document.write( "120/11 = x<BR>\n" );
document.write( " </SPAN>\n" );
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