document.write( "Question 181145This question is from textbook algebra 2
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document.write( ": solve:\r
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document.write( "square root of x-6- square root of 1/3x=0 \n" );
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Algebra.Com's Answer #135813 by eperette(173)![]() ![]() ![]() You can put this solution on YOUR website! I am assuming it is (1/3)x= x/3....not 1/(3x)\r \n" ); document.write( "\n" ); document.write( "sqr(x-6) - sqr((1/3)x)=0 \n" ); document.write( "sqr(x-6) = sqr (1/3x) \n" ); document.write( "(sqr(x-6))^2 = (sqr(1/3x))^2 \n" ); document.write( "x-6 = 1/3x \n" ); document.write( "x-1/3x -6 = 1/3x - 1/3x \n" ); document.write( "2/3x - 6 = 0 \n" ); document.write( "2/3x-6+6 = 0+6 \n" ); document.write( "2/3x = 6 \n" ); document.write( "3(2/3x) = 6(3) \n" ); document.write( "2x = 18 \n" ); document.write( "2x/2 = 18/2 \n" ); document.write( "x = 9\r \n" ); document.write( "\n" ); document.write( "check\r \n" ); document.write( "\n" ); document.write( "sqr(9-6) - sqr(1/3 * 9) \n" ); document.write( "sqr(3) - sqr (9/3) \n" ); document.write( "sqr(3) - sqr (3) \n" ); document.write( "0\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |