document.write( "Question 181145This question is from textbook algebra 2
\n" ); document.write( ": solve:\r
\n" ); document.write( "\n" ); document.write( "square root of x-6- square root of 1/3x=0
\n" ); document.write( "

Algebra.Com's Answer #135813 by eperette(173)\"\" \"About 
You can put this solution on YOUR website!
I am assuming it is (1/3)x= x/3....not 1/(3x)\r
\n" ); document.write( "\n" ); document.write( "sqr(x-6) - sqr((1/3)x)=0
\n" ); document.write( "sqr(x-6) = sqr (1/3x)
\n" ); document.write( "(sqr(x-6))^2 = (sqr(1/3x))^2
\n" ); document.write( "x-6 = 1/3x
\n" ); document.write( "x-1/3x -6 = 1/3x - 1/3x
\n" ); document.write( "2/3x - 6 = 0
\n" ); document.write( "2/3x-6+6 = 0+6
\n" ); document.write( "2/3x = 6
\n" ); document.write( "3(2/3x) = 6(3)
\n" ); document.write( "2x = 18
\n" ); document.write( "2x/2 = 18/2
\n" ); document.write( "x = 9\r
\n" ); document.write( "\n" ); document.write( "check\r
\n" ); document.write( "\n" ); document.write( "sqr(9-6) - sqr(1/3 * 9)
\n" ); document.write( "sqr(3) - sqr (9/3)
\n" ); document.write( "sqr(3) - sqr (3)
\n" ); document.write( "0\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );