document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=181149>Question 181149</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The distance(d) is directly proportional to time (t) and d = 15 km after 2 1/2 hrs, then after 3 hrs more d is ?<BR>\n" );
document.write( "OH GOODNESS PLEASE HELP </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #135804 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=135804\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The distance(d) is directly proportional to time (t) and d = 15 km after 2 1/2 hrs, then after 3 hrs more d is ?<BR>\n" );
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document.write( "In other words, the longer you drive (or run, or move by any means) the farther you go.<BR>\n" );
document.write( "distance = rate*time<BR>\n" );
document.write( "15 = r*2.5<BR>\n" );
document.write( "r = 15/2.5<BR>\n" );
document.write( "r = 6 km/hr<BR>\n" );
document.write( "d2 = 6*3 (rate*time)<BR>\n" );
document.write( "d2 = 18 km\r<BR>\n" );
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