document.write( "Question 181151: If y varies inversely as 3x +2 and y=24 when x =1 , find x when y is 15?
\n" ); document.write( "Help a guy out?
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Algebra.Com's Answer #135803 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
If y varies inversely as 3x +2 and y=24 when x =1
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\n" ); document.write( "y = k/(3x+2)
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\n" ); document.write( "Solve for \"k\":
\n" ); document.write( "24 = k/(3*1+2)
\n" ); document.write( "24 = k/5
\n" ); document.write( "k = 120
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\n" ); document.write( "Equation:
\n" ); document.write( "y = 120/(3x+2)
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\n" ); document.write( "Find x when y is 15?\r
\n" ); document.write( "\n" ); document.write( "15 = 120/(3x+2)\r
\n" ); document.write( "\n" ); document.write( "Cross-multiply:
\n" ); document.write( "3x+2 = 120/15
\n" ); document.write( "3x + 2 = 8
\n" ); document.write( "3x = 6
\n" ); document.write( "x = 2
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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