document.write( "Question 181114: two military squads are 26 miles apart. they plan to rendezvous at some intermediate point. if one squad hikes 2/3 mph faster than the other, and they meet in 3 hrs, what is the rate of the faster squad? \n" ); document.write( "

Algebra.Com's Answer #135791 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let $\"r\"$ = the rate of the slower squad
\n" ); document.write( "Let $\"d\"$ = the distance the slower squad travels in 3 hrs
\n" ); document.write( "given:
\n" ); document.write( "The rate of the faster squad is
\n" ); document.write( " $\"%28r+%2B+%282%2F3%29%29\"$
\n" ); document.write( "The distance the faster squad travels in 3 hrs is
\n" ); document.write( " $\"26+-+d\"$
\n" ); document.write( "---------------------
\n" ); document.write( "For slower squad:
\n" ); document.write( "(1) $\"d+=+3r\"$
\n" ); document.write( "For faster squad:
\n" ); document.write( " $\"26+-+d+=+%28r+%2B+%282%2F3%29%29%2A3\"$
\n" ); document.write( " $\"26+-+d+=+3r+%2B+2\"$
\n" ); document.write( "(2) $\"d+=+24+-+3r\"$
\n" ); document.write( "Subtract (1) from (2)
\n" ); document.write( "(2) $\"d+=+24+-+3r\"$
\n" ); document.write( "(1) $\"-d+=+-3r\"$
\n" ); document.write( " $\"0+=+24+-+6r\"$
\n" ); document.write( " $\"6r+=+24\"$
\n" ); document.write( " $\"r+=+4\"$ mi/hr
\n" ); document.write( "The rate of the faster squad is
\n" ); document.write( " $\"r+%2B+%282%2F3%29+=+4.67\"$ mi/hr
\n" ); document.write( "The faster squad's rate was 4.67 mi/hr
\n" ); document.write( "check answer
\n" ); document.write( " $\"d+=+3r\"$
\n" ); document.write( " $\"d+=+12\"$ mi
\n" ); document.write( " $\"26+-+d+=+%28r+%2B+%282%2F3%29%29%2A3\"$
\n" ); document.write( " $\"26+-+12+=+%28r+%2B+%282%2F3%29%29%2A3\"$
\n" ); document.write( " $\"14++=+3r+%2B+2\"$
\n" ); document.write( " $\"3r+=+12\"$
\n" ); document.write( " $\"r+=+4\"$ mi/hr
\n" ); document.write( "OK \n" ); document.write( "

\n" );