document.write( "Question 181113: a man jogged to his friend's house at a rate of 6 mph. the trip took 20 minutes. how long will it take him to return home if he can maintain a rate of 8 mph? \n" ); document.write( "
Algebra.Com's Answer #135787 by ankor@dixie-net.com(22740)\"\" \"About 
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a man jogged to his friend's house at a rate of 6 mph. the trip took 20 minutes.
\n" ); document.write( " how long will it take him to return home if he can maintain a rate of 8 mph?
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\n" ); document.write( "Let t = time required in min to return home
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\n" ); document.write( "We don't have to convert to mph here
\n" ); document.write( "6*20 = 8t
\n" ); document.write( "120 = 8t
\n" ); document.write( "t = 120/8
\n" ); document.write( "t = 15 min to return
\n" ); document.write( ":
\n" ); document.write( "Find the dist in mi by using hrs to check it:
\n" ); document.write( "6mph * \"1%2F3\"hr = 2 mi
\n" ); document.write( "8mph * \"1%2F4\"hr = 2 mi
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