document.write( "Question 181114: two military squads are 26 miles apart. they plan to rendezvous at some intermediate point. if one squad hikes 2/3 mph faster than the other, and they meet in 3 hrs, what is the rate of the faster squad? \n" ); document.write( "
Algebra.Com's Answer #135786 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! two military squads are 26 miles apart. they plan to rendezvous at some \n" ); document.write( " intermediate point. if one squad hikes 2/3 mph faster than the other, \n" ); document.write( " and they meet in 3 hrs, what is the rate of the faster squad? \n" ); document.write( ": \n" ); document.write( "Let s = the speed of the faster squad \n" ); document.write( "then \n" ); document.write( "(s- \n" ); document.write( ": \n" ); document.write( "The total dist of both squads = 26 mi, they both travel for 3 hrs: \n" ); document.write( "write a distance equation dist = time * speed \n" ); document.write( ": \n" ); document.write( "3s + 3(s- \n" ); document.write( "Multiply what's inside the brackets \n" ); document.write( "3s + 3s - 2 = 26 \n" ); document.write( "6s = 26 + 2 \n" ); document.write( "6s = 28 \n" ); document.write( "s = \n" ); document.write( "s = 14/3 or 4 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "check solution by finding the dist traveled by each (slower squad = 4 mph) \n" ); document.write( "3 * 4 = 12 \n" ); document.write( "3 * \n" ); document.write( "------------ \n" ); document.write( "Total 26 mi \n" ); document.write( " |