document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=181126>Question 181126</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/9780136007319/algebrahomeworkh>Beginning & Intermediate Algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> I was wondering if someone might be able to show me how to use the substitution process to solve the folling linear equation. I can do it but the one like this confuses me. Please show me step by step how this one is done.<BR>\n" );
document.write( "x+y=3<BR>\n" );
document.write( "x=2y-------this is what is confusing me since x is already solved for.\r<BR>\n" );
document.write( "\n" );
document.write( "Thanks for any help anyone is able to give!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #135779 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=135779\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x+y=3<BR>\n" );
document.write( "x=2y-------this is what is confusing me since x is already solved for. <BR>\n" );
document.write( "-------------<BR>\n" );
document.write( "Since x is already \"solved for\", expressed in terms of y, substitute x into the other eqn.<BR>\n" );
document.write( "2y + y = 3<BR>\n" );
document.write( "3y = 3<BR>\n" );
document.write( "y = 1<BR>\n" );
document.write( "-----------<BR>\n" );
document.write( "x = 2y<BR>\n" );
document.write( "x = 2<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );