document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=25321>Question 25321</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please explain how to solve 8(4-u)+u=8+u. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #13577 by </B><A HREF=/tutors/aboutme.mpl?userid=longjonsilver><B>longjonsilver(2297)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=longjonsilver><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=longjonsilver><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=13577\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First, get rid of the brackets so that we just have a collection of terms to add or subtract...\r<BR>\n" );
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document.write( "8(4-u)+u=8+u<BR>\n" );
document.write( "32-8u+u = 8+u\r<BR>\n" );
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document.write( "Now collect like terms (i shall do it in 2 stages)<BR>\n" );
document.write( "32-7u = 8+u<BR>\n" );
document.write( "and then<BR>\n" );
document.write( "32-8u = 8<BR>\n" );
document.write( "-8u = -24\r<BR>\n" );
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document.write( "Now divide by -8 to find what u is:<BR>\n" );
document.write( "u = -24/-8<BR>\n" );
document.write( "u = +3\r<BR>\n" );
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document.write( "jon.<BR>\n" );
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