document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=181073>Question 181073</A>: <I><SPAN STYLE=\"word-break: break-all;\"> sHOW HOW THEY EQUAL<BR>\n" );
document.write( "tan 60 degrees- tan 30 degrees/1+ tan 60 degrees tan 30 degrees = tan 30 degrees.<BR>\n" );
document.write( "HEY CAN SOMEONE HELP, I AM LOST </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #135729 by </B><A HREF=/tutors/aboutme.mpl?userid=eperette><B>eperette(173)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=eperette><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=135729\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> THINGS YOU SHOULD KNOW:<BR>\n" );
document.write( "tan60= sin60/cos60 = (sqr(3)/2)/(1/2)= sqr(3)<BR>\n" );
document.write( "tan30= sin30/cos30 = (1/2)/(sqr(3)/2)= 1/sqr(3)= sqr(3)/3\r<BR>\n" );
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document.write( "(tan60-tan30)/(1+tan60tan30)<BR>\n" );
document.write( "(sqr(3)-sqr(3)/3)/(1+sqr(3)*1/sqr(3))<BR>\n" );
document.write( "(3sqr(3)/3 - sqr(3)/3)/ (1+1)<BR>\n" );
document.write( "(2sqr(3)/3)/ (2)<BR>\n" );
document.write( "(2sqr(3)/3)(1/2)<BR>\n" );
document.write( "sqr(3)/3\r<BR>\n" );
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document.write( "and sqr(3)/3=tan30 </SPAN>\n" );
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