document.write( "Question 181067: In (triangle)PQR, m(angle)\n" ); document.write( "Hey can someone help, dont get it... \n" ); document.write( "

Algebra.Com's Answer #135728 by Alan3354(69443) $\"\"$ $\"About$

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In (triangle)PQR, m(angle)\n" ); document.write( "Hey can someone help, dont get it...
\n" ); document.write( "----------------------
\n" ); document.write( "It's a right triangle, so find PR using Pythagoras:
\n" ); document.write( " $\"PR+=+sqrt%281%5E1+%2B+3%5E2%29\"$
\n" ); document.write( " $\"PR+=+sqrt%2810%29\"$
\n" ); document.write( "Then, sec(R) = PR/QR
\n" ); document.write( "sec(R) = 1/cos(R)
\n" ); document.write( " $\"sec%28R%29+=+sqrt%2810%29%2F3\"$
\n" ); document.write( "=~ 1.0541 \n" ); document.write( "

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