document.write( "Question 181074: PLEASE PLEASE HELP!!!!!!!!!!!!!!!!!
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document.write( "show that they equal.
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document.write( "1 + cot 30 degrees cot 60 degrees/cot 30 degrees-cot 60 degrees=cot 30 degrees. \n" );
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Algebra.Com's Answer #135726 by eperette(173)![]() ![]() ![]() You can put this solution on YOUR website! THINGS YOU SHOULD KNOW: \n" ); document.write( "cot 30 = cos 30/sin30 = (sqr(3)/2)/(1/2)= sqr(3) \n" ); document.write( "cot 60 = cos60/sin60 = (1/2)/ (sqr (3)/2)= 1/ sqr(3) = sqr(3)/3\r \n" ); document.write( "\n" ); document.write( "(1 + cot30 cot60)/ (cot30-cot60) \n" ); document.write( "(1 + sqr(3)*sqr(3)/3)/ (sqr(3)- sqr(3)/3) \n" ); document.write( "(1 + 3/3)/ (3sqr(3)/3 - sqr(3)/3) \n" ); document.write( "(1 + 1)/ (2sqr(3)/3) \n" ); document.write( "2/ (2sqr(3)/3) \n" ); document.write( "(2/1)(3/ 2sqr(3)) \n" ); document.write( "3/sqr(3) \n" ); document.write( "3/sqr(3) * (sqr(3)/sqr(3)) \n" ); document.write( "3sqr(3)/3 \n" ); document.write( "sqr(3)\r \n" ); document.write( "\n" ); document.write( "and sqr(3)= cot30 \n" ); document.write( " |