document.write( "Question 181013: If I have 100 ft. of fencing and I want to enclose the most area, should I make the enclosure a circle, triangle, or a square Prove your answer. \n" ); document.write( "
Algebra.Com's Answer #135675 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! If I have 100 ft. of fencing and I want to enclose the most area, should I make the enclosure a circle, triangle, or a square Prove your answer. \n" ); document.write( "-------------------------- \n" ); document.write( "With only 3 to choose from, it's a matter of determining area vs. perimiter. \n" ); document.write( "Circle: \n" ); document.write( "C = 2*pi*r = 100 \n" ); document.write( "r = 50/pi \n" ); document.write( "Area = pi*r^2 \n" ); document.write( "Area = pi*(50/pi)^2 \n" ); document.write( "Area = 2500/pi =~795.8 sq ft \n" ); document.write( "----------------------- \n" ); document.write( "Square: \n" ); document.write( "C = 4s = 100 feet \n" ); document.write( "s = 25 ft \n" ); document.write( "Area = 25^2 = 625 sq ft \n" ); document.write( "------------------ \n" ); document.write( "Triangle (equilateral): \n" ); document.write( "C = 3s = 100 feet \n" ); document.write( "s = 100/3 feet \n" ); document.write( "Area = bh/2 \n" ); document.write( "Area = s*(s/2)*sqrt(3)/2 \n" ); document.write( "Area = s^2*sqrt(3)/4 \n" ); document.write( "Area =~ 481 sq ft \n" ); document.write( "------------------- \n" ); document.write( "The circle encloses the greatest area. \n" ); document.write( "--------------- \n" ); document.write( "The enclosed area increases with the number of sides of the polygon, and is a maximum when the # of sides is infinite, which is a circle. \n" ); document.write( " |