document.write( "Question 180966This question is from textbook College Algebra
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document.write( ": Mary and Chris, together can clean their house in 2 hours. Mary alone can clean the house in 3 hours and 30 minutes. How long does it take Chris to clean the house working alone? \n" );
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Algebra.Com's Answer #135662 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! Let x=amount of time it takes Chris working alone to clean the house \n" ); document.write( "Chris therefore works at the rate of 1/x house per hour \n" ); document.write( "Mary and Chris working together works at the rate of 1/2 house per hour \n" ); document.write( "Mary alone works at the rate of 1/(3.5) house per hour\r \n" ); document.write( "\n" ); document.write( "Now we are told that: \n" ); document.write( " 1/x + 1/(3.5)=1/2 multiply each term by 7x \n" ); document.write( "7+2x=3.5x subtract 2x from each side \n" ); document.write( "7=3.5x-2x \n" ); document.write( "1.5x=7 \n" ); document.write( "x=4 2/3 hours------------------amount of time it takes Chris working alone \n" ); document.write( "4 2/3=14/3 \n" ); document.write( "3 1/2=7/2 \n" ); document.write( "3/14 +2/7=1/2 \n" ); document.write( "3/14+4/14=1/2 \n" ); document.write( "1/2=1/2\r \n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor \n" ); document.write( " |