document.write( "Question 180961This question is from textbook College Algebra
\n" ); document.write( ": An 8 liter container in the lab is full of 40% acid solution. A Student working in the lab accidentally spills some of the solution and to hide his mistake he fills up the container with pure water. If the new solution is 30% acid, how much did he spill? \n" ); document.write( "
Algebra.Com's Answer #135661 by ptaylor(2198)\"\" \"About 
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\n" ); document.write( "Let x=amount of the 40% solution that is spilled and the amount of pure water that is added back\r
\n" ); document.write( "\n" ); document.write( "Now we know that the amount of pure acid remaining after the spill(0.40(8-x)) has to equal the amount of pure acid that is in the final solution after the water is added(0.30*8). So our equation to solve is:
\n" ); document.write( "0.40(8-x)=0.30*8 get rid of parens
\n" ); document.write( "3.2-0.40x=2.4 subtract 3.2 from each side
\n" ); document.write( "3.2-3.2-0.40x=2.4-3.2 collect like terms
\n" ); document.write( "-0.40x=--0.8
\n" ); document.write( "x=2 liters------------------------amount that was spilled\r
\n" ); document.write( "\n" ); document.write( "CK
\n" ); document.write( "0.40*6=0.30*8
\n" ); document.write( "2.4=2.4\r
\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor
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