document.write( "Question 180852: a train normally travels 240km at a certain speed. one day, due to bad weather, the train's speed is reduced by 20km/h so that the journey takes two hours longer. find the normal speed. \n" ); document.write( "
Algebra.Com's Answer #135624 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! a train normally travels 240km at a certain speed. one day, due to bad weather, the train's speed is reduced by 20km/h so that the journey takes two hours longer. find the normal speed. \n" ); document.write( "----------------------------- \n" ); document.write( "Normal-travel DATA: \n" ); document.write( "distance = 240 km ; rate = x km/h ; time = d/r = 240/x hrs \n" ); document.write( "--------------------- \n" ); document.write( "Bad weather DATA: \n" ); document.write( "distance = 240 km ; rate = (x-20) km/h ;time = 240/(x-20) hrs \n" ); document.write( "------------------------------------ \n" ); document.write( "Bad time - normal time = 2 hrs \n" ); document.write( "240/(x-20) - 240/x = 2 \n" ); document.write( "120/(x-20) - 120/x = 1\r \n" ); document.write( "\n" ); document.write( "120x -120(x-20) = x(x-20)\r \n" ); document.write( "\n" ); document.write( "20 = x^2 -20x \n" ); document.write( "x^2 - 20x - 20 = 0\r \n" ); document.write( "\n" ); document.write( "x = [20 +- sqrt(20^2 - 4*1*-20)]/2\r \n" ); document.write( "\n" ); document.write( "x = [20 +- sqrt(480)]/2\r \n" ); document.write( "\n" ); document.write( "x = [20 +- 4sqrt(30)]/2\r \n" ); document.write( "\n" ); document.write( "x = 10 +- 2sqrt(30) \n" ); document.write( "=========================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |