document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=169528>Question 169528</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If I walk 1/2 mile north and 1 1/2 mile east how many miles can I walk back with taking two miles to return. I need to know the shorter distance back to my main starting point. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #135599 by </B><A HREF=/tutors/aboutme.mpl?userid=cloudstrifeo0o><B>cloudstrifeo0o(5)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=cloudstrifeo0o><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=135599\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Well, First lets use the Theorem: a^2 + b^2 = c^2\r<BR>\n" );
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document.write( "You walked 1/2 mi. North, and 1 1/2 mi. East.<BR>\n" );
document.write( " .5^2 + 1.5^2 = c^2 Work out the squares.\r<BR>\n" );
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document.write( ".25 + 2.25 = c^2 Add.<BR>\n" );
document.write( "2.5 = c^2 Now square root.<BR>\n" );
document.write( "sqrt2.5 = sqrtc^2\r<BR>\n" );
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document.write( "1.58113883... or 1.6 = c\r<BR>\n" );
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document.write( "From what I could understand from you question, that would be your distance. </SPAN>\n" );
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