document.write( "Question 180847: Ok, I have been working on these two since 4 30 this morning and still can't figure them out. Could somebody help me before I go nuts?
\n" ); document.write( "One is (z-6)^2-40=0 and 2x^2+7x+2=0 I keep getting some odd ball numbers and have not a clue what to do with them. Thanks in advance, Judy \n" ); document.write( "

Algebra.Com's Answer #135586 by stanbon(75887) $\"\"$ $\"About$

You can put this solution on YOUR website!
(z-6)^2-40=0 \r
\n" ); document.write( "\n" ); document.write( "z^2-12z+36-40 =0\r
\n" ); document.write( "\n" ); document.write( "z^2 - 12z - 4 = 0
\n" ); document.write( "Use the quadratic formula to get:\r
\n" ); document.write( "\n" ); document.write( "z = [12 +- sqrt(12^2 - 4*1*-4)]/2\r
\n" ); document.write( "\n" ); document.write( "z = [12 +- sqrt(160)]/2\r
\n" ); document.write( "\n" ); document.write( "z = [12 +- 4sqrt(10)]/2\r
\n" ); document.write( "\n" ); document.write( "z = 6 +- 2sqrt(10)
\n" ); document.write( "==========================\r
\n" ); document.write( "\n" ); document.write( "2x^2+7x+2=0 \r
\n" ); document.write( "\n" ); document.write( "Use the quadratic forula to get:\r
\n" ); document.write( "\n" ); document.write( "x = [-7 +- sqrt(7^2 -4*2*2)]/4\r
\n" ); document.write( "\n" ); document.write( "x = [-7 +- sqrt(33)]/4\r
\n" ); document.write( "\n" ); document.write( "x = (-7/4) +- (1/4)sqrt(33)
\n" ); document.write( "===============================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( " \n" ); document.write( "

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