document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=180834>Question 180834</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the derivative.<BR>\n" );
document.write( "1. x = ln(x+y+1)\r<BR>\n" );
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document.write( "and \r<BR>\n" );
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document.write( "2. F(x) = (square root of quantity 1 + x)- ln(1 + square root of quantity x + 1)  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #135578 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=135578\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> find the derivative.<BR>\n" );
document.write( "1. x = ln(x+y+1) \r<BR>\n" );
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document.write( "1 = [1/(x+y+1)](1 + (y'))\r<BR>\n" );
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document.write( "y' = [x+y+1] -1<BR>\n" );
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document.write( "and <BR>\n" );
document.write( "2. F(x) = sqrt(1 + x)- ln[1 + sqrt(x + 1)]\r<BR>\n" );
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document.write( "F'(x) = (1/2)(1+x)^(-1/2) - [1/(1+sqrt(x+1)] * [(1/2)(x+1)^(-1/2)]<BR>\n" );
document.write( "====================================================================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. <BR>\n" );
document.write( " </SPAN>\n" );
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