document.write( "Question 180757: The (x,y) is the solution set to the system 2x-y=-4
\n" ); document.write( " 5x+9y=13, then
\n" ); document.write( "a. -3 \n" ); document.write( "b. 0\n" ); document.write( "c. -3 \n" ); document.write( "d. 0\n" ); document.write( "

Algebra.Com's Answer #135569 by Mathtut(3670)\"\" \"About 
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The (x,y) is the solution set to the system 2x-y=-4
\n" ); document.write( " 5x+9y=13, then
\n" ); document.write( "a. -3 \n" ); document.write( "b. 0\n" ); document.write( "c. -3 \n" ); document.write( "d. 0\n" ); document.write( "\n" ); document.write( "2x-y=-4.....eq 1
\n" ); document.write( "5x+9y=13....eq 2
\n" ); document.write( ":
\n" ); document.write( "rewrite eq 1 to y=2x+4 and plug that value into eq 2
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\n" ); document.write( "5x+9(2x+4)=13
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\n" ); document.write( "5x+18x+36=13
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\n" ); document.write( "23x=-23
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\n" ); document.write( "\"highlight%28x=-1%29\"
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\n" ); document.write( "plug x's found value into eq 1 or 2 . I choose eq 1
\n" ); document.write( ":
\n" ); document.write( "2(-1)-y=-4
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\n" ); document.write( "\"highlight%28y=2%29\"
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\n" ); document.write( "so we have x=-1 and y=2
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\n" ); document.write( "therefore c is the answer
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