document.write( "Question 25248: 1. 2(x+1)=3x-1.\r
\n" ); document.write( "\n" ); document.write( "2. 6(x+1)=12(x-3).
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Algebra.Com's Answer #13556 by elima(1433)\"\" \"About 
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1. 2(x+1)=3x-1.
\n" ); document.write( "First distribute the 2;
\n" ); document.write( "2x+2=3x-1
\n" ); document.write( "subtract 3x and 2 from each side;
\n" ); document.write( "2x-3x=-1-2
\n" ); document.write( "-x=-3
\n" ); document.write( "x=3
\n" ); document.write( "2. 6(x+1)=12(x-3).
\n" ); document.write( "Distribute the 6 and 12;
\n" ); document.write( "6x+6=12x-36
\n" ); document.write( "subtract 12x and add 6 to each side;
\n" ); document.write( "6x-12x=-36+6
\n" ); document.write( "-6x=-30
\n" ); document.write( "x=5
\n" ); document.write( "Hope this helps
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