document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=180817>Question 180817</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I know you subtract 8 from 2 and get: (3/x) = -6 but I don't know what to do after. \r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #135558 by </B><A HREF=/tutors/aboutme.mpl?userid=eperette><B>eperette(173)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=eperette><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=135558\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (3/x) + 8 = 2<BR>\n" );
document.write( "(3/x) + 8 -8 = 2 -8<BR>\n" );
document.write( "(3/x) = -6<BR>\n" );
document.write( "x(3/x = -6)<BR>\n" );
document.write( "3x/x = -6x<BR>\n" );
document.write( "3 = -6x<BR>\n" );
document.write( "3/-6 = -6x/-6<BR>\n" );
document.write( "-1/2 = x<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );