document.write( "Question 180813: Solve Variation Problem\r
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document.write( "The cost of pipe at Home Depo varies jointly as the length and
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document.write( "diameter of the pipe. If 20 feet of 0.5 inch diameter pipe
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document.write( "costs $36.60, then what is the cost of 12 feet of 0.75 inch
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document.write( "diameter pipe? \n" );
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Algebra.Com's Answer #135550 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Solve Variation Problem \n" ); document.write( "The cost of pipe at Home Depo varies jointly as the length and \n" ); document.write( "diameter of the pipe. \n" ); document.write( "--- \n" ); document.write( "c = k \n" ); document.write( "--\r \n" ); document.write( "\n" ); document.write( "If 20 feet of 0.5 inch diameter pipe \n" ); document.write( "costs $36.60 \n" ); document.write( "Solve for \"k\": \n" ); document.write( "36.60 = k[20*0.5]\r \n" ); document.write( "\n" ); document.write( "k = 36.60/10 = 3.66 \n" ); document.write( "--- \n" ); document.write( "Equation: \n" ); document.write( "c = 3.66[Ld] \n" ); document.write( "---\r \n" ); document.write( "\n" ); document.write( ", then what is the cost of 12 feet of 0.75 inch \n" ); document.write( "diameter pipe? \n" ); document.write( "--- \n" ); document.write( "c = 3.66[12*0.75] \n" ); document.write( "cost = 3.66*9 \n" ); document.write( "cost = $32.94 \n" ); document.write( "===================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |