document.write( "Question 180667: On a trip of 800 km , Charlie drove at two different speeds. \in one province he drove at 100 km/h and in another at 110 km/h. If the entire trip took seven and one-half hours, the distance travelled at the 110 km/h speed is? \n" ); document.write( "

Algebra.Com's Answer #135545 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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On a trip of 800 km , Charlie drove at two different speeds.
\n" ); document.write( "\in one province he drove at 100 km/h and in another at 110 km/h.
\n" ); document.write( " If the entire trip took seven and one-half hours, the distance traveled at the 110 km/h speed is?
\n" ); document.write( ";
\n" ); document.write( "Let d = distance traveled at 110 km/hr
\n" ); document.write( "then
\n" ); document.write( "(800-d) = distance traveled at 100 km/hr
\n" ); document.write( ";
\n" ); document.write( "Write time equation: Time = dist/speed
\n" ); document.write( ";
\n" ); document.write( "hrs at 110 + hrs at 100 = 7 $\"1%2F2\"$ hrs
\n" ); document.write( " $\"d%2F110\"$ + $\"%28%28800-d%29%29%2F100\"$ = 7.5
\n" ); document.write( ":
\n" ); document.write( "Multiply equation by 1100 to get rid of the denominators
\n" ); document.write( "1100* $\"d%2F110\"$ + 1100* $\"%28%28800-d%29%29%2F100\"$ = 1100(7.5)
\n" ); document.write( "Results
\n" ); document.write( "10d + 11(800-d) = 8250
\n" ); document.write( ":
\n" ); document.write( "10d + 8800 - 11d = 8250
\n" ); document.write( ":
\n" ); document.write( "10d - 11d = 8250 - 8800
\n" ); document.write( ":
\n" ); document.write( "-d = -550
\n" ); document.write( ":
\n" ); document.write( "d = 550 km at 110 km/hr
\n" ); document.write( ";
\n" ); document.write( ":
\n" ); document.write( "Check solution by finding the actual times at each speed (800-550 = 250)
\n" ); document.write( "550/110 = 5 hrs
\n" ); document.write( "250/100 = 2.5 hrs
\n" ); document.write( "------------------
\n" ); document.write( "total hrs 7.5 \n" ); document.write( "

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