document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=180804>Question 180804</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the Variation Problem\r<BR>\n" );
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document.write( "The frequency of a vibrating string varies inversely as its length. A string 3 feet long vibrates 175 cycles per second. Find the frequency of a 5 foot string. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #135543 by </B><A HREF=/tutors/aboutme.mpl?userid=eperette><B>eperette(173)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=eperette><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=135543\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Concept: Inverse Variation<BR>\n" );
document.write( "If F varies inversely with L then F=k/L, where k is a constant (number)\r<BR>\n" );
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document.write( "Know:  Usually in this problems, you have to find the constant before you can continue to find other frequencies or lenghts \r<BR>\n" );
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document.write( "Answer:<BR>\n" );
document.write( "F=k/L<BR>\n" );
document.write( "175= k/3<BR>\n" );
document.write( "3(175=k/3)<BR>\n" );
document.write( "3(175) = 3(k/3)<BR>\n" );
document.write( "525 = k<BR>\n" );
document.write( "*****<BR>\n" );
document.write( "Then F = 525/5<BR>\n" );
document.write( "F= 105 </SPAN>\n" );
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