document.write( "Question 180732: Find the slope of the tangent to the curve at the given point:\r
\n" ); document.write( "\n" ); document.write( "f(x)=(√16-x), where y=5
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Algebra.Com's Answer #135465 by Alan3354(69443)\"\" \"About 
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Find the slope of the tangent to the curve at the given point:
\n" ); document.write( "f(x)=(√16-x), where y=5
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\n" ); document.write( "\"y+=+%2816-x%29%5E%281%2F2%29\"
\n" ); document.write( "@y=5:
\n" ); document.write( "\"5+=+%2816-x%29%5E%281%2F2%29\"
\n" ); document.write( "25 = 16-x
\n" ); document.write( "x = -9
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\n" ); document.write( "\"dy%2Fdx+=+%281%2F2%29%2A%2816-x%29%5E%28-1%2F2%29%2A%28-1%29\"
\n" ); document.write( "@x = -9:
\n" ); document.write( "y' = (-1/2)/5
\n" ); document.write( "y' = -1/10\r
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