document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=180678>Question 180678</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Could you please help me solve this, I have been trying for two days and I am not understanding what I am doing wrong. Thank you soooo much!!!!\r<BR>\n" );
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document.write( "THe directions state to solve each by substitution and determine whether the equation is independent, dependent, or inconsistent.\r<BR>\n" );
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document.write( "2y=x+6 (this is the first part)\r<BR>\n" );
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document.write( "-3x+2y=-2 (this is the second part)<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #135414 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=135414\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solve the system of equations:<BR>\n" );
document.write( "1) <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%282y%29+=+highlight%28x%2B6%29 ALIGN=MIDDLE  ALT=\"highlight%282y%29+=+highlight%28x%2B6%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "2) <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-3x%2Bhighlight%282y%29+=+-2 ALIGN=MIDDLE  ALT=\"-3x%2Bhighlight%282y%29+=+-2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Substitute equation 1) for the 2y in equation 2).<BR>\n" );
document.write( "2a)<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-3x%2Bhighlight%28x%2B6%29+=+-2 ALIGN=MIDDLE  ALT=\"-3x%2Bhighlight%28x%2B6%29+=+-2\"   DISABLED_style= \"max-width:90%; height:auto;\" > Simplify and solve for x by comining the x's.<BR>\n" );
document.write( "2a)<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-2x%2B6+=+-2 ALIGN=MIDDLE  ALT=\"-2x%2B6+=+-2\"   DISABLED_style= \"max-width:90%; height:auto;\" > Subtract 6 from both sides of the equation.<BR>\n" );
document.write( "2a)<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-2x+=+-8 ALIGN=MIDDLE  ALT=\"-2x+=+-8\"   DISABLED_style= \"max-width:90%; height:auto;\" > Divide both sides by -2.<BR>\n" );
document.write( "2a)<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+4 ALIGN=MIDDLE  ALT=\"x+=+4\"   DISABLED_style= \"max-width:90%; height:auto;\" > Now substitute this value of x into either one of the original equations to find y. Let's use equation 1).<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2y+=+x%2B6 ALIGN=MIDDLE  ALT=\"2y+=+x%2B6\"   DISABLED_style= \"max-width:90%; height:auto;\" > Substitute x = 4.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2y+=+4%2B6 ALIGN=MIDDLE  ALT=\"2y+=+4%2B6\"   DISABLED_style= \"max-width:90%; height:auto;\" > <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2y+=+10 ALIGN=MIDDLE  ALT=\"2y+=+10\"   DISABLED_style= \"max-width:90%; height:auto;\" > Divide both sides by 2.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+5 ALIGN=MIDDLE  ALT=\"y+=+5\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "The solution is: (4, 5) which is the intersection point of the two lines represented by the two linear equation.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=graph%28400%2C400%2C-3%2C8%2C-3%2C8%2C%28x%2F2%29%2B3%2C%283%2F2%29x-1%29 ALIGN=MIDDLE  ALT=\"graph%28400%2C400%2C-3%2C8%2C-3%2C8%2C%28x%2F2%29%2B3%2C%283%2F2%29x-1%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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