document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=180621>Question 180621</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Not all visitors to a certain company's website are customers. In fact, the website administrator estimates that about 12% of all visitors to the website are looking for other websites. Assuming that this estimate is correct, find the probability that, in a random sample of 5 visitors to the website, exactly 4 actually are looking for the website. \r<BR>\n" );
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document.write( "Round your response to at least three decimal places. \r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #135401 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=135401\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Not all visitors to a certain company's website are customers. In fact, the website administrator estimates that about 12% of all visitors to the website are looking for other websites. Assuming that this estimate is correct, find the probability that, in a random sample of 5 visitors to the website, exactly 4 actually are looking for the website. <BR>\n" );
document.write( "Round your response to at least three decimal places. <BR>\n" );
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document.write( "It's a binomial problem with n = 5, p = 0.12 ; x = 4<BR>\n" );
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document.write( "P(x=4) = 5C4(0.12)^4(0.88)^1 = 5*(0.00030736)(0.88) = 0.000912384..<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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