document.write( "Question 25281: Solve & show steps:\r
\n" ); document.write( "\n" ); document.write( "5x - 5 = 3x - 7 + 2(x + 1) \n" ); document.write( "
Algebra.Com's Answer #13539 by AnlytcPhil(1806)\"\" \"About 
You can put this solution on YOUR website!
5x - 5 = 3x - 7 + 2(x + 1)\r\n" );
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document.write( "First remove the parentheses on the RHS by \r\n" );
document.write( "multiplying each term inside the parentheses \r\n" );
document.write( "by the outer multiplier 2:\r\n" );
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document.write( "5x - 5 = 3x - 7 + 2x + 2\r\n" );
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document.write( "Combine the 3x and the 2x on the RHS as 5x; \r\n" );
document.write( "also combine the -7 and the +2 as -5\r\n" );
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document.write( "5x - 5 = 5x - 5\r\n" );
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document.write( "Add 5 to both sides\r\n" );
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document.write( "5x - 5 + 5 = 5x - 5 + 5\r\n" );
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document.write( "        5x = 5x\r\n" );
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document.write( "Subtract 5x from both sides\r\n" );
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document.write( "   5x - 5x = 5x - 5x\r\n" );
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document.write( "         0 = 0\r\n" );
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document.write( "The 0 on the left should be thought of as 0x\r\n" );
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document.write( "        0x = 0\r\n" );
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document.write( "Now we see that any number can replace x and\r\n" );
document.write( "the equation will be true, that is\r\n" );
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document.write( "      0(1) = 0\r\n" );
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document.write( "      0(0) = 0\r\n" );
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document.write( "     0(-7) = 0\r\n" );
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document.write( "   0(9999) = 0\r\n" );
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document.write( "  0(11/17) = 0\r\n" );
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document.write( "etc., etc., etc.\r\n" );
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document.write( "Therefore we say x can be any real number.\r\n" );
document.write( "This kind of equation is called an identity.\r\n" );
document.write( "Every number is a solution to it.\r\n" );
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document.write( "Edwin\r\n" );
document.write( "AnlytcPhil@aol.com
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