document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=180595>Question 180595</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Re-arrange this equation to find x in terms of y and t.\r<BR>\n" );
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document.write( "2t(x - 2t) = y(x - y)\r<BR>\n" );
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document.write( "I really need to know how to work this out and not just the answer.\r<BR>\n" );
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document.write( "I expanded the brackets to get: 2tx - 4t^2 = xy - y^2<BR>\n" );
document.write( "Then I put all of the x terms on the LHS:  2tx - xy = 4t^2 - y^2\r<BR>\n" );
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document.write( "The I wasn't sure where to go after that.\r<BR>\n" );
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document.write( "The question did not come from a text book, it was a past paper question\r<BR>\n" );
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document.write( "Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #135356 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=135356\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2t(x - 2t) = y(x - y)<BR>\n" );
document.write( "2tx-4t^2=xy-y^2<BR>\n" );
document.write( "2tx-xy=4t^2-y^2<BR>\n" );
document.write( "x(2t-y)=4t^2-y^2<BR>\n" );
document.write( "x=(4t^2-y^2)/(2t-y) <BR>\n" );
document.write( "x=(2t+y)(2t-y)/(2t-y)<BR>\n" );
document.write( "x=2t+y ans. </SPAN>\n" );
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