document.write( "Question 180563: A business invests $8,000 in a savings account for two years. At the beginning of the second year an additional $2,500 is invested. At the end of the second year, the account balance is $11,445. What was the annual interest rate? \n" ); document.write( "
Algebra.Com's Answer #135331 by Mathtut(3670)\"\" \"About 
You can put this solution on YOUR website!
assuming the interest rate is the same for both amounts invested
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\n" ); document.write( "\"8000%2B8000x%2B%288000%2B8000x%29x%2B2500%2B2500x=11445\"
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\n" ); document.write( "\"8000%2B8000x%2B8000x%2B8000x%5E2%2B2500%2B2500x=11445\"
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\n" ); document.write( "\"8000x%5E2%2B18500x-945=0\"
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\n" ); document.write( "x=.05 and -2.36
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\n" ); document.write( "throw out the negative
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\n" ); document.write( "interest rate is \".05%28100%29=highlight%285%29\"%
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Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"8000x%5E2%2B18500x%2B-945+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%2818500%29%5E2-4%2A8000%2A-945=372490000\".
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\n" ); document.write( " Discriminant d=372490000 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-18500%2B-sqrt%28+372490000+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"x%5B1%5D+=+%28-%2818500%29%2Bsqrt%28+372490000+%29%29%2F2%5C8000+=+0.05\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%2818500%29-sqrt%28+372490000+%29%29%2F2%5C8000+=+-2.3625\"
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\n" ); document.write( " Quadratic expression \"8000x%5E2%2B18500x%2B-945\" can be factored:
\n" ); document.write( " \"8000x%5E2%2B18500x%2B-945+=+%28x-0.05%29%2A%28x--2.3625%29\"
\n" ); document.write( " Again, the answer is: 0.05, -2.3625.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+8000%2Ax%5E2%2B18500%2Ax%2B-945+%29\"
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