document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=180568>Question 180568</A>: <I><SPAN STYLE=\"word-break: break-all;\"> i don't get how to do this at all: \r<BR>\n" );
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document.write( "it says to graph the equation:\r<BR>\n" );
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document.write( "6y+5 = 5y+3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #135327 by </B><A HREF=/tutors/aboutme.mpl?userid=mgmoeab><B>mgmoeab(37)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mgmoeab><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mgmoeab><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=135327\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The only thing you need to do is solve for 'y'\r<BR>\n" );
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document.write( "6y + 5 = 5y + 3<BR>\n" );
document.write( "PUT LIKE-TERMS ON THE SAME SIDE OF THE EQUATION\r<BR>\n" );
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document.write( "6y - 5y = 3 - 5<BR>\n" );
document.write( "  y = -2 <--- you would only have to graph this line. <BR>\n" );
document.write( "Horizontal line which passes through point (x, 2) \r<BR>\n" );
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document.write( "  </SPAN>\n" );
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